BRO1141: Object creation with an initializer: parentheses in one style¶

An object creation with an initializer and no arguments is written without the empty parentheses (new List<int> { 1 }, the default) or with them (new List<int>() { 1 }). Not a StyleCop rule (Roslynator RCS1050).

Example¶

Before¶

using System.Collections.Generic;

public class Settings
{
    public string Name { get; set; } = "";

    public List<int> Ports = new List<int>() { 80, 443 };

    public static Settings Default() => new Settings() { Name = "default" };
}

After¶

using System.Collections.Generic;

public class Settings
{
    public string Name { get; set; } = "";

    public List<int> Ports = new List<int> { 80, 443 };

    public static Settings Default() => new Settings { Name = "default" };
}

Why¶

The parentheses say nothing when there are no arguments; the initializer shows that an object is built. One way to write it keeps creations consistent.

How the fix works¶

omit removes the parentheses and any spaces before them; include inserts () right after the type.

Configuration¶

[*.cs]
# omit (default): new List<int> { 1 }; include: new List<int>() { 1 }
stylebro_object_creation_parentheses = omit

Not reported¶

Creations with arguments (new List<int>(4) { 1 }) or without an initializer (new List<int>()).
Target-typed new() { ... }: it needs its parentheses.
A comment between the type and the parentheses.

Compared with StyleCop¶

StyleCop has no such rule. stylebro-migrate turns it off (see Rules beyond StyleCop).